(x^2+2x-8)(x^2-16)=0

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Solution for (x^2+2x-8)(x^2-16)=0 equation:


Simplifying
(x2 + 2x + -8)(x2 + -16) = 0

Reorder the terms:
(-8 + 2x + x2)(x2 + -16) = 0

Reorder the terms:
(-8 + 2x + x2)(-16 + x2) = 0

Multiply (-8 + 2x + x2) * (-16 + x2)
(-8(-16 + x2) + 2x * (-16 + x2) + x2(-16 + x2)) = 0
((-16 * -8 + x2 * -8) + 2x * (-16 + x2) + x2(-16 + x2)) = 0
((128 + -8x2) + 2x * (-16 + x2) + x2(-16 + x2)) = 0
(128 + -8x2 + (-16 * 2x + x2 * 2x) + x2(-16 + x2)) = 0
(128 + -8x2 + (-32x + 2x3) + x2(-16 + x2)) = 0
(128 + -8x2 + -32x + 2x3 + (-16 * x2 + x2 * x2)) = 0
(128 + -8x2 + -32x + 2x3 + (-16x2 + x4)) = 0

Reorder the terms:
(128 + -32x + -8x2 + -16x2 + 2x3 + x4) = 0

Combine like terms: -8x2 + -16x2 = -24x2
(128 + -32x + -24x2 + 2x3 + x4) = 0

Solving
128 + -32x + -24x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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